Q. 263.7( 3 Votes )

The angle of elevation of the top of a tower at a point on the ground 50 m away from the foot of the tower is 45°. Then the height of the tower (in metres) is
A. 50√3

B. 50

C.

D.

Answer :


Let AB be the tower of h meters height forming angle of elevation= 45° from 50m distance from the tower


In Δ ABC


tan 45° =


h = 50 m

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