Q. 113.9( 29 Votes )

# The shadow of a tower, when the angle of elevation of the sun is 45°, is found to be 10 m longer than when it was 60°. Find the height of the tower.

Answer :

Let the height of the tower = h (m)

Let the point of 60° elevation is (m) away from the foot of the tower.

In ∆ABC,

tan 45° =

1 =

1 =

h = 10+ ----(1)

In ∆ABD,

tan 60° =

√3 =

h = √3

= ---------(2)

From eqn. (2) in eqn. (1)

h =

h - = 10

= 10

= 10√3

⇒

h= ⇒ h=

⇒ 15+5√3 ⇒ 23.66 m.

Therefore height of the tower is 23.66 m.

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUSA person observed the angle of elevation of the top of a tower as 30°. He walked 50 m towards the foot of the tower along level ground and found the angle of elevation of the top of the tower as 60°. Find the height of the tower.NEXTA parachutist is descending vertically and makes angles of elevation of 45° and 60° at two observing points 100 m apart from each other on the left side of himself. Find the maximum height from which he falls and the distance of the point where he falls on the ground from the just observation point.

Related Videos

Trick to learn all Trigonometric Formulae28 mins

Champ Quiz | Trigger on Trigonometry47 mins

Fundas of Trigonometry50 mins

Champ Quiz | Trigonometry Important Questions33 mins

NCERT | Trigonometric Identities52 mins

Champ Quiz | NTSE Trigonometry50 mins

Testing the T- Ratios of Specified Angles57 mins

Foundation | Cracking Previous Year IMO QuestionsFREE Class

NCERT | Imp. Qs. on Trigonometry42 mins

Quiz | Trail of Mixed Questions on Trigonometry59 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation