Q. 243.8( 4 Votes )

The angle of depression of a car parked on the road from the top of a 150 m high tower is 30°. The distance of the car from the tower (in metres) is
A. 50√3

B. 150√3

C. 150√2

D. 75

Answer :


Here AB is the tower of 150m which forms the angel of depression = 30° from the top


Hence the angle of elevation from the car is 90° - 30° = 60°


In Δ ABC


tan 60° =


BC =


BC = 50 √3 m

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