# A T.V. tower stan

Let BC be the height of the T.V tower and AB be the width of the river.

In ∆ABC,

tan 60° =

√3 = ------(1)

In ∆ABC,

tan 30° =

tan 30° =

=

√3h = 20+ ---------(2)

On substituting value of h in eqn.(2)

√3× √3 = 20+

3

3

2

On substituting value of in eqn. (1)

h = √3

h = 10√3 m.

Therefore height of T.V tower is 10√3 m. and width of river is 10 m.

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