In figure (5-E11)

Give:

m₁= 5 kg, m₂ = 2 kg and F = 1 N

Let the acceleration of the blocks be a.

From the free-body diagram, m₁a = m₁g + F − T …(i)

Again, from the free-body diagram, m₂a = T − m₂g − F …(ii)

Adding equations (i) and (ii), we have:

⇒ a= =4.2 m/s²

Hence, acceleration of the block is 4.2 m/s².

After the string breaks, m₁ moves downward with force F acting downward. Then,

m₁a = F + m₁g

5a = 1 + 5g

g = +0.2 m/s²