Q. 27

In figure (5-E11) m1 = 5 kg, m2 = kg and F = 1 N. Find the acceleration of either block. Describe the motion of m if the string breaks but F continues to act.

Answer :


m1= 5 kg, m2 = 2 kg and F = 1 N

Let the acceleration of the blocks be a.

From the free-body diagram, m1a = m1g + F − T …(i)

Again, from the free-body diagram, m2a = T − m2g − F …(ii)

Adding equations (i) and (ii), we have:

a= =4.2 m/s2

Hence, acceleration of the block is 4.2 m/s2.

After the string breaks, m1 moves downward with force F acting downward. Then,

m1a = F + m1g

5a = 1 + 5g

g = +0.2 m/s2

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