Q. 27

In figure (5-E11) m1 = 5 kg, m2 = kg and F = 1 N. Find the acceleration of either block. Describe the motion of m if the string breaks but F continues to act.

Answer :


Give:


m1= 5 kg, m2 = 2 kg and F = 1 N


Let the acceleration of the blocks be a.


From the free-body diagram, m1a = m1g + F − T …(i)


Again, from the free-body diagram, m2a = T − m2g − F …(ii)


Adding equations (i) and (ii), we have:



a= =4.2 m/s2


Hence, acceleration of the block is 4.2 m/s2.


After the string breaks, m1 moves downward with force F acting downward. Then,


m1a = F + m1g


5a = 1 + 5g



g = +0.2 m/s2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Pseudo Force52 mins
Pully Problems | Getting JEE Ready68 mins
Challenging Quiz on Newton Laws of Motion Part 364 mins
Elaborative Lecture on Constraint Motion59 mins
Escaping the reality - Concept of Pseudo Force54 mins
Concept of Linear momentum and its conservation40 mins
Check your understanding of linear momentum22 mins
Why edges are raised for Curved roads? - Banking of roads54 mins
Into the world of springs - Spring force48 mins
Basics strengthener - Newton Laws of motion61 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :