Q. 225.0( 3 Votes )

In a simple Atwood machine, two unequal masses m1 and m2 are connected by a string going over a clamped light smooth pulley. In a typical arrangement (figure 5-E7) m1 = 300 g and m2 = 600 g. The system is released from rest. (a) Find the distance travelled by the first block in the first two seconds. (b) Find the tension in the string, (c) Find the force exerted by the clamp on the pulley.



Answer :


Let acceleration of the blocks be


Let tension in the string be T


Given:


Mass m1=300 g=0.3 kg


Mass m2=600 g=0.6 kg


Let the mass 1 be moving upward and mass 2 moves downward


Equation for mass 1,


-----(1)


Equation for mass 2,


------(2)


Adding both the equation we get,



Now putting the values, we get,



i)


Using the equation of motion,


Where u=initial velocity = 0 m/s and tie t=2s



ii) From equation (1), we get,





iii) Force on the clamp is due to tension from both side of the pulley, i.e., twice of tension


required force


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