Answer :

Let the acceleration of mass M be a.
So, the acceleration of mass 2M will be


Ma = 2T
T + Ma − Mg = 0


3Ma=2Mg a=

(b) Tension,

(c) Let T' = resultant of tensions
T=T2+T2=2 T

T=2T =√ Again, tanθ= =1 θ=45°

So, the force exerted by the clamp on the pulley is √(2mg/3) at an angle of 45° with the horizontal.

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