Answer :


Let the acceleration of mass M be a.
So, the acceleration of mass 2M will be


(a)


Ma = 2T
T + Ma − Mg = 0

Ma2+Ma=Mg


3Ma=2Mg a=


(b) Tension,


(c) Let T' = resultant of tensions
T=T2+T2=2 T


T=2T =√ Again, tanθ= =1 θ=45°


So, the force exerted by the clamp on the pulley is √(2mg/3) at an angle of 45° with the horizontal.


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