Answer :

Suppose the monkey accelerates upwards with acceleration ' a ' and the block, accelerate downwards with acceleration a₁.

Let force exerted by monkey is equal to ' T '.

From the free body diagram of monkey,

T - mg - ma = 0 ........ ( i )

T = mg + ma

From the free body diagram of block, T = ma₁ - mg = 0

mg + ma + ma - mg = 0 [From eq (i)]

ma = - ma

a = - a

The block & the monkey move in the same direction with equal acceleration. If initially they are rest (no force is exerted by monkey) no motion of monkey of block occurs as they have same weight (same mass). Their separation will not change as time passes.

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