Q. 233.6( 7 Votes )

Consider the Atwood machine of the previous problem. The larger mass is stopped for a moment 2.0 s after the system is set into motion. Find the time elapsed before the string is tight again.

Answer :

mass=m1 =300g, mass=m2=600g.

When masses m1 and m2 are connected by a string passing over a pulley and when the pulley comes in motion, then mass m2 is stopped in 2 seconds. So, equation of motion is:


T m1 g = m1 a−−−−(1)


m2 g T = m2 a−−−−(2)


On solving equations (1) and (2), we get,


a = = = ms-2


In 2 second the velocity acquired by mass m1 is given by,


Applying first equation of motion,


0 = v ×2 or v = ms-1


with acceleration due to gravity i. e.


0 = − 10 t or t = = sec


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