Answer :

It is given that mass of the block is m=20kg

A) The reading of the balance = Tension in the string

And tension in the string = 20 ×10 = 200 N

So, the reading of the balance = = 200 N

B) If the balance is heavy, the reading will not change because the weight of spring balance does not affect the tension in the string

Therefore, Tension is equal to

C) If the blocks have unequal masses, the spring balance will accelerate towards the block with heavy higher mass with an acceleration a.

Then, Reading = tension in the string.

Suppose m1 > m2.

Then tension in the string,

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