Answer :

Let the angles of quadrilateral be (a – 3d) °, (a – d) °, (a + d) ° and (a + 3d) °.


We know that the sum of angles of a quadrilateral is 360°.


a – 3d + a – d + a + d + a + 3d = 360°


4a = 360°


a = 90°


Given the greatest angle = 120°


a + 3d = 120°


90° + 3d = 120°


3d = 120° - 90°


3d = 30°


d = 10°


Hence, the angles are:


(a – 3d) ° = 90° - 30° = 60°


(a – d) ° = 90° - 10° = 80°


(a + d) ° = 90° + 10° = 100°


(a + 3d) ° = 120°


Angles of quadrilateral in radians:






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