# The angles of a q

Let the angles of quadrilateral be (a – 3d) °, (a – d) °, (a + d) ° and (a + 3d) °.

We know that the sum of angles of a quadrilateral is 360°.

a – 3d + a – d + a + d + a + 3d = 360°

4a = 360°

a = 90°

Given the greatest angle = 120°

a + 3d = 120°

90° + 3d = 120°

3d = 120° - 90°

3d = 30°

d = 10°

Hence, the angles are:

(a – 3d) ° = 90° - 30° = 60°

(a – d) ° = 90° - 10° = 80°

(a + d) ° = 90° + 10° = 100°

(a + 3d) ° = 120°    Rate this question :

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