Q. 24

# Figure (5-E8) shows a uniform rod of length 30 cm having a mass of 3.0 kg. The strings shown in the figure are pulled by constant forces of 20 N and 32 N. Find the force exerted by the 20 cm part of the rod on the 10 cm part. All the surfaces are smooth and the strings and the pulleys are light.

Resultant force = 32 - 20 = 12 N

Acceleration of the block = = = 4 m/s2 (towards right)

m1= 3 kg × () = 1 kg

m2 = 3 kg × () = 2 kg

Force exerted by m1 on m2 = m1a = 1*4 = 4 N = Force exerted by m2 on m

Therefore, total force = 20 + 4 = 24 N

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Pseudo Force52 mins
Elaborative Lecture on Constraint Motion59 mins
Pully Problems | Getting JEE Ready68 mins
Challenging Quiz on Newton Laws of Motion Part 364 mins
Check your understanding of linear momentum22 mins
Why edges are raised for Curved roads? - Banking of roads54 mins
Into the world of springs - Spring force48 mins
Basics strengthener - Newton Laws of motion61 mins
Understand Newton's 2nd law Exhaustively34 mins
Escaping the reality - Concept of Pseudo Force54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses