Q. 364.3( 6 Votes )

A monkey of mass 15 kg is climbing on a rope with one end fixed to the ceiling. If it wishes w go up with an acceleration of
1 m/s2, how much force should it apply to the rope? If the rope is 5 m long and the monkey starts from rest, how much time will it take to reach the ceiling?

Answer :



Acceleration of the monkey in the upward direction, a = 1 m/s2

The free-body diagram of the monkey is given in the attachment:

From the free-body diagram:

T − [15g + 15(a)] = 0

T − [15g + 15(1)] = 0

T = 5 (10 + 1)

T = 15 × 11 = 165 N

The monkey should apply a force of 165 N to the rope.

Initial velocity, u = 0, s = 5 m

Using, s = ut+at �, we get: 5=0+×1×t �

t =5×2 t=10 s

Hence, the time required to reach the ceiling is 10 s.

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