Q. 34

# Find the acceleration of the blocks A and B in the three situations shown in figure(5-E 17).  Given: 5a + T − 5g = 0

From free-body diagram (1), T = 5g − 5a …..(i) T 8g 16a = 0

From free-body diagram (2),

T = 8g + 16a ……(ii)

From equations (i) and (ii), we get:

5g − 5a = 8g + 16a So, the acceleration of the 5 kg mass is 97 m/s2 upward and that of the 4 kg mass is 2a= downward.

(b) From free body diagram (3), 8a T = 0

T = 8a

Again, T + 5a − 5g = 0

From free body diagram-4, 8a + 5a − 5g = 0

13a 5g = 0 downward

(c) T + 1a − 1g = 0

From free body diagram, T = 1g − 1a …..(i)

Again, from free body diagram T 4g 8a = 0 ..(ii)

From equation (i) 1g − 1a − 4g − 8a = 0 downward

Acceleration of mass 1 kg is upward, Acceleration of mass 2 kg is downward

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Pseudo Force52 mins  Challenging Quiz on Newton Laws of Motion Part 364 mins  Pully Problems | Getting JEE Ready68 mins  Understand Newton's 2nd law Exhaustively34 mins  Basics strengthener - Newton Laws of motion61 mins  Check your understanding of linear momentum22 mins  Why edges are raised for Curved roads? - Banking of roads54 mins  Into the world of springs - Spring force48 mins  Elaborative Lecture on Constraint Motion59 mins  Escaping the reality - Concept of Pseudo Force54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 