Answer :


Given:


The two bodies are separated because the elevator is moving downward with an acceleration of 12 ms-2 (>g) and the body moves with acceleration, g = 10 ms-2 [Freely falling body]


Now, for the block: g = 10 m/s �, u = 0, t = 0.2 s


So, the distance travelled by the block is given by



=5×0.04 =0.2 m =20 cm


The displacement of the body is 20 cm during the first 0.2 s


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Figure <span langPhysics - Exemplar

Figure <span langPhysics - Exemplar

A block of known HC Verma - Concepts of Physics Part 1

The energy of a sHC Verma - Concepts of Physics Part 1