# A pendulum bob of

Given: mass of the bob = 50g = 0.05 kg

When the elevator is at rest the tension in the string weight of the bob

a) When it goes up with an acceleration in upward direction a pseudo force acts on the bob in downward direction.

The tension in the string becomes=

b) When it goes up with a deceleration in upward direction a pseudo force acts on the bob in downward direction with negative sign.

The tension in the string becomes=s=

c) When it goes up with a uniform velocity in upward direction no pseudo force acts on the bob in downward direction.

The tension in the string becomes=s=

d) When it goes down with an acceleration in downward direction a pseudo force acts on the bob in upward direction.

The tension in the string becomes=s=

e) When it goes down with a deceleration in downward direction a pseudo force acts on the bob in upnward direction with negative sign.

The tension in the string becomes=s=

f) When it goes up with uniform velocity in downward direction no pseudo force.

The tension in the string becomes=

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