Answer :

Given: mass of the bob = 50g = 0.05 kg


When the elevator is at rest the tension in the string weight of the bob


a) When it goes up with an acceleration in upward direction a pseudo force acts on the bob in downward direction.


The tension in the string becomes=



b) When it goes up with a deceleration in upward direction a pseudo force acts on the bob in downward direction with negative sign.


The tension in the string becomes=s=



c) When it goes up with a uniform velocity in upward direction no pseudo force acts on the bob in downward direction.


The tension in the string becomes=s=



d) When it goes down with an acceleration in downward direction a pseudo force acts on the bob in upward direction.


The tension in the string becomes=s=



e) When it goes down with a deceleration in downward direction a pseudo force acts on the bob in upnward direction with negative sign.


The tension in the string becomes=s=



f) When it goes up with uniform velocity in downward direction no pseudo force.


The tension in the string becomes=



Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Figure <span langPhysics - Exemplar

Figure <span langPhysics - Exemplar

Two uniform solidHC Verma - Concepts of Physics Part 1

A block of known HC Verma - Concepts of Physics Part 1