Q. 54.1( 15 Votes )

# A block of mass m is placed on a smooth inclined plane of inclination θ with the horizontal. The force exerted by the plane on the block has a magnitude

A. mg

B. mg/cosθ

C. mg cosθ

D. mg tanθ

Answer :

From the free-body diagram,

The force exerted by the mass m on the plane is.

Since the action and reaction are equal and opposite, the force exerted by the plane on the block will be in a direction opposite to the normal component of the force exerted by the block on the plane.*Therefore,* *N = mg* cosθ

Normal force exerted by the plane on the block is *mg* cosθ.

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