Q. 403.9( 7 Votes )

A block A can slide on a frictionless incline of angle θ and length l, kept inside an elevator going up with uniform velocity u (figure 5-E22). Find the time taken by the block to slide down the length of the incline if it is released from the top of the incline.

Answer :


The force on the block which makes the body move down the plane is the component of its weight parallel to the inclined surface.

F = mg sinθ

Acceleration, g = sin θ

Initial velocity of block, u = 0

Distance to be covered ,s = l

a = g sin θ

Using, , we get:

Time taken, t=

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Pseudo Force52 mins
Challenging Quiz on Newton Laws of Motion Part 364 mins
Elaborative Lecture on Constraint Motion59 mins
Pully Problems | Getting JEE Ready68 mins
Check your understanding of linear momentum22 mins
Why edges are raised for Curved roads? - Banking of roads54 mins
Into the world of springs - Spring force48 mins
Basics strengthener - Newton Laws of motion61 mins
Understand Newton's 2nd law Exhaustively34 mins
Escaping the reality - Concept of Pseudo Force54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses