Answer :

(i) According to Avogadro’s Law,

1 mole of Argon 6.023×1023 atoms of Argon

So, 52 moles of Argon X atoms of Argon

X =52×6.023×1023


Therefore in 52 moles of Argon 3.13196×1025 atoms are present.

(ii) Atomic Mass of Helium [He] = 4 u

This means that mass of one atom of Helium is = 4 u

So, Number of atom of Helium contained in 52 u = 52/4= 13 atoms

Therefore, in 52 u of Helium 13 atoms are present.

(iii) Atomic Mass of Helium [He] = 4 u

Number of Moles of Helium in 52 g = 52/4= 13 moles

So, Number of atoms in 52g of Helium [He] = 13×6.023×1023= 7.8299×1024

Therefore, in 52 g of Helium 7.83×1024 atoms are present.

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