Answer :
f(x) = -x3+3x2-3x+4.
f’(x) = -3x2+6x-3
f’(x) = -3(x2-2x+1)
f’(x) = -3(x-1)2
As f’(x) has –ve sign before 3
⇒ f’(x) is decreasing over R.
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