Q. 74

# Mark (√) against the correct answer in the following: is increasing inA. (-2, 0)B. (0, 2)C. (2, ∞)D. (-∞, ∞)

Given f(x) = x2.e-x

f’(x) = 2x. e-x – x2 e-x

Put f’(x) = 0

- (x2– 2x)e-x = 0

x = 0 or x =2.

Now as there is a -ve sign before f’(x)

When x>2 the function is decreasing

x<0 function is decreasing

But in the interval (0,2) the function is increasing.

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