Answer :

Given:


f(x) = 3x+cos3x


f’(x) = 3-3sin3x


f’(x) = 3(1-sin3x)


sin3x varies from[-1,1]


when sin3x is 1 f’(x) = 0 and sin3x is -1 f’(x) = 6


As the function is increasing in 0 to 6.


The function is increasing on R.

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