f(x) = 3x+cos3x
f’(x) = 3-3sin3x
f’(x) = 3(1-sin3x)
sin3x varies from[-1,1]
when sin3x is 1 f’(x) = 0 and sin3x is -1 f’(x) = 6
As the function is increasing in 0 to 6.
∴ The function is increasing on R.
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