Q. 134.0( 1 Vote )
Mark (√) against A. -1
B. 1
C. 
D. none of these
Answer :
Given that x+y=sin(x+y)
Differentiating with respect to x, we get
or 
Hence, cos(x+y)=1 or 
If cos(x+y)=1 then, x+y=2nπ, n∈ℤ
Hence x+y=sin(2nπ)=0 or y=-x
Differentiating with respect to x, we get
Hence, 
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