Q. 14

# The pressure p and the volume V of a gas are connected by the relation, , where k is a constant. Find the percentage increase in the pressure, corresponding to a diminution of 0.5% in the volume.

Given: pv1/4 = k

%decrease in the volume = 1/2%s

pv1/4 = k

taking log on both sides

log[pv1/4] = log a

log P + 1.4logV = log a

Differentiating both the sides we get

Multiplying both sides by 100.

%error in P = 0.7%.

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