Q. 55.0( 2 Votes )

# Divide a into two

Answer :

Given,

• the number ‘a’ is divided into two numbers.

• the product of the pth power of one number and qth power of another number is maximum.

Let us consider,

• x and y are the two numbers

• Sum of the numbers : x + y = a

• Product of square of the one number and cube of anther number : P = x^{p} y^{q}

Now as,

x + y = a

y = (a-x) ------ (1)

Consider,

P = x^{p}y^{q}

By substituting (1), we have

P = x^{p} × (a-x)^{q} ------ (2)

For finding the maximum/ minimum of given function, we can find it by differentiating it with x and then equating it to zero. __This is because if the function f(x) has a maximum/minimum at a point c then f’(c) = 0.__

Differentiating the equation (2) with x

[Since and if u and v are two functions of x, then ]

= x^{p-1}(a-x)^{q-1}[ap-xp-xq]

= x^{p-1}(a-x)^{q-1}[ap – x (p+q)] ----- (3)

Now equating the first derivative to zero will give the critical point c.

So,

Hence x^{p-1} = 0 (or) (a-x)^{q-1} (or) ap– x(p+q)= 0

x = 0 (or) x = a (or)

Now considering the critical values of x = 0,a and

Now, using the First Derivative test,

__For f, a continuous function which has a critical point c, then, function has the local maximum at c, if f’(x) changes the sign from positive to negative as x increases through c, i.e. f’(x)>0 at every point close to the left of c and f’(x)<0 at every point close to the right of c.__

Now when x = 0,

So, we reject x = 0

Now when x = a,

Hence we reject x = a

Now when ,

> 0 ---- (4)

Now when ,

< 0 ---- (5)

By using first derivative test, from (4) and (5), we can conclude that, the function P has local maximum at

From Equation (1), if

Therefore, and are the two positive numbers whose sum together to give the number ‘a’ and whose product of the pth power of one number and qth power of the other number is maximum.

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