Answer :

local max. value is 0 at x = 2 and local min. value is 4 at x = 0

f(x)=(x-1)2(x+2)+(x+2)2=0


x=0,-2


f’’(0)>0, 0 is the point of local min.


f’’(-2)<0, -2 is the point of local max.


f(0)=-4


f(-2)=0


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