Find the point on

Slope of y = x – 11 is equal to 1

3x² – 11 = 1 ⇒ x = 2 and -2

At x = 2

From the equation of curve, y = (2)³ – 11(2) + 5 = -9

From the equation of tangent, y = 2 – 11 = -9

At x = -2

From the equation of curve, y = (-2)³ – 11(-2) + 5 = 19

From the equation of tangent, y = -2 – 11 = -13

So, the final answer is (2, -9) because at x = -2, y is come different from the equation of curve and tangent which is not possible.