Q. 73

Mark (√) against A. (0, e)

B.

C. (0,1 )

D. none of these

Answer :

Given: f(x) = xx.


f'(x)=(log x+1) xx


keeping f’(x) = 0


We get



Now


When x>1/e the function is increasing


x<0 function is increasing.


But in the interval (0,1/e) the function is decreasing.

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