Q. 235.0( 1 Vote )
Discuss the appli
Since, f(x)=x1/2 is a polynomial and we know every polynomial function is continuous for all xϵR.
⇒ f(x)= x1/2 is continuous on [-1,1].
Here, which does not exist at x=0 in [-1,1].
f(x)=x1/2 is not differentiable on (-1,1).
Condition (2) of Rolle’s theorem is not satisfied.
So,Rolle’s theorem is not applicable.
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