Q. 9

Answer :

local max. value is 19 at x = 1 and local min. value is 15 at x = 3

F^{’}(x)=3x^{2}-12x+9=0

⇒3(x-3)(x-1)=0

⇒ x=3,1

F^{’’}(x)=6x-12

F^{’’}(3)=18-12=6>0 , 3 is the of local min.

F^{’’}(1)<0, 1 is the point of local max.

F(3)=15

F(1)=19

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