Answer :

local max. value is 19 at x = 1 and local min. value is 15 at x = 3

F(x)=3x2-12x+9=0


3(x-3)(x-1)=0


x=3,1


F’’(x)=6x-12


F’’(3)=18-12=6>0 , 3 is the of local min.


F’’(1)<0, 1 is the point of local max.


F(3)=15


F(1)=19


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