Answer :

local max. value is 68 at x = 1 and local min. values are 1647 at x = 6 and 316 at x = 5

F’(x)=4x3-124x+120=0


4(x3-31x+30)=0


For x=1, the given eq is 0


؞x-1 is a factor,


4(x-1)(x+6)(x-5)=0


X=1,-6,5


F’’(1)<0, 1is the point of max.


F’’(-6) and f’’(5)>0, -6 and 5 are point of min.


F(1)=68


F(-6)=-1647


F(5)=-316


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