Answer :

local max. value is 3 at x = 1 and local min. value is 128 at x = 6

F(x)=6x2-42x+36=0


6(x-1)(x-6)=0


x=1,6


F’’(x)=12x-42


F’’(1)<0 ,1 is the pont of local max.


F’’(6)>0, 6 is the point of localmin.


F(1)=2-21+36-20=-3


F(6)=-128


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