# A 5 V battery is

A

(b) Since two resistors of 20 ohm are connected in series, the effective resistance will be

R= R1 +R2

Here, R1 = 20 ohm

R2 = 20 ohm

Therefore the effective resistance of the two resistors = 20+20 =40 ohm

(c) Current flowing through the circuit = I = V/R = 5/40 = 0.125 amps

(d) p.d. across each resistance = I x R = 0.125 x 20 = 2.5 V

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