Answer :
A

(b) Since two resistors of 20 ohm are connected in series, the effective resistance will be
R= R1 +R2
Here, R1 = 20 ohm
R2 = 20 ohm
Therefore the effective resistance of the two resistors = 20+20 =40 ohm
(c) Current flowing through the circuit = I = V/R = 5/40 = 0.125 amps
(d) p.d. across each resistance = I x R = 0.125 x 20 = 2.5 V
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Electricity-245 mins
Electricity-144 mins
Resistors in Series33 mins
Electric Power39 mins
Electric Current35 mins
Resistance43 mins
Resistors in Parallel36 mins
Heating Effect of Electric Current42 mins

Electricity-245 mins
Electricity-144 mins
Resistors in Series33 mins
Electric Power39 mins
Electric Current35 mins
Resistance43 mins
Resistors in Parallel36 mins
Heating Effect of Electric Current42 minsTry our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
In a series combi
Science Lab ManualWhat is the equiv
Science Lab ManualWhy are copper an
Science Lab Manual