Answer :


Let the current be I amperes and the battery be of strength V volts. Let the combined resistance of the three resistors be R ohms.


Therefore, according to Ohm's law, we have


V= IR -----(i)


We know that when the resistors are connected in series, the current is the same in all the resistors. Therefore


V= V1 +V2+ V3 ------------------ (ii)


Let the current flowing through the whole circuit is I, and the equivalent resistance be R.


According to ohm's law


V= IR


V1= IR1 -------- (iii)


V2= IR2-------- (iv)


V3= IR3 ------ (v)


By using eq (i),(ii),(iii) ,(iv) and (v) we get


IR= IR1+ IR2+ IR3


R= R1+ R2+ R3


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