Q. 7

# In a house two 60

When two electric bulb of 60W are lighted for 4 hours then

Here, p1 = 60w

Number, n1 = 2

Time for daily use, t1 = 4h

Total electrical consumed everyday, E1 = n1×p1×t1

= 2×60×4 = 480

Energy consumed in 30 days = 30×0.48 = 14.4Kwh (As 1kW=1000W)

When three electric bulb of 100W are lighted for 5 hours then

Here, p2 = 100w

Number, n2 = 3

Time for daily use, t2 = 5h

Total electrical consumed every day, E1 = n2×p2×t2

= 3×100×5 = 1500

Energy consumed in 30 days = 30× 1.5 = 45Kwh (As 1kW= 1000 W)

Total electrical consumed in 30 days = 14.4Kwh + 45Kwh = 59.4 kWh

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