Answer :

The resistance of 6 ohm and 3 ohm are connected in series. Therefore, their net resistance can be calculated as

R= R1+R2


Here, R1= 6ohm


R2= 3ohm


so R= 6ohm +3ohm= 9 ohm


The current through 6 ohm resistor= current through line 1 = I= V/R =4/9=0.44V


(ii) The resistance of 12ohm and 3 ohm are connected in series. Therefore, their net resistance can be calculated as


R= R1+R2


Here, R1= 12ohm


R2= 3ohm


so R= 12ohm +3ohm= 15 ohm


The current through them = I= V/R =4/15


Potential difference across 12 ohm resistor= 4/15 ×12 =3.2


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