Answer :

Let the current in the circuit be I amperes and the battery be of strength V volts. Let the combined resistance of the three resistors be R ohms.

Therefore, according to Ohm's law, we have

V=IR ---- (i)

We know that when resistors are connected in series, the current with a battery of V volts.

V_{1}=I×R_{1} ------- (ii)

V_{2} =I×R_{2} ------ (iii)

Let the potential difference across R_{1} is V_{1} and the potential difference across R_{2} is V_{2}

V=V_{1}+V_{2}--------- (iv)

From equation (i),(ii), (iii) and (iv) we get.

IR= I×R_{1}+ I×R_{2}

R= R_{1}+ R_{2}

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