Answer :

Let the current in the circuit be I amperes and the battery be of strength V volts. Let the combined resistance of the three resistors be R ohms.

Therefore, according to Ohm's law, we have

V=IR ---- (i)

We know that when resistors are connected in series, the current with a battery of V volts.

V1=I×R1 ------- (ii)

V2 =I×R2 ------ (iii)

Let the potential difference across R1 is V1 and the potential difference across R2 is V2

V=V1+V2--------- (iv)

From equation (i),(ii), (iii) and (iv) we get.

IR= I×R1+ I×R2

R= R1+ R2

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