Q. 4 A3.8( 13 Votes )

# Explain with the

Answer : Let the resistance of the three resistors be R1, R2 and R3, respectively. Let their combined resistance be R.

Let the total current flowing in the circuit be I and the strength of the battery be V. Then from Ohm's law, we have: V= IR------- (1)

We know that when the resistors are connected in parallel, the potential drop across each resistance is the same. Therefore:

I = I1+I2+I3

I = V/R1+ V/R2+ V/R3

1/R=1/R1+1/R2+ 1/R3

If two resistances are connected in parallel, then the resultant resistance will be

1/R=1/R1+1/R2+ 1/R3

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