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Lakhmir Singh & Manjit Kaur - Physics

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Q. 123.9( 18 Votes )

Calculate the pow

Class 10th Lakhmir Singh & Manjit Kaur - Physics 1. Electricity

Answer :

(a) Here V = 6 volt, R₁ = 1 ohm, R₂ = 2 ohm

The connection is in series. So Equivalent resistance = R₁+R₂ = 1 + 2 = 3 ohm

We know that

Total current I = V/R = 6/3 = 2A

Current through R₂ = I₂ = I = 2A

Voltage across R₂ = V₂ = I₂R₂ = 2×2 = 4 ohm

Power used in R₂ = I₂V₂ = 2×4 = 8W

(b) Here, V = 4 volt,R₁ = 12 ohm, R₂ = 2 ohm

We know that, as the connection is in parallel so voltage across R₂ = V₂ = V = 4V

Current across R₂ = I₂ = V₂/R₂ = 4/2 = 2A

As power = IV

Power used in R₂ = I₂V₂ = 2×4 = 8W

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