Answer :

(a) To obtain the highest resistance we must connect the given resistances in series.

Highest resistance R = 4 + 8 + 12 + 24 = 48ohms


(b) To obtain the lowest resistance we must connect the given resistances in parallel.


1/R=1/4+1/8+1/12+1/24


On solving we get, R=2ohms


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

In a series combiScience Lab Manual

What is the equivScience Lab Manual

Why are copper anScience Lab Manual