Answer :

(i) As shown in the figure, the resistor R2 and R3 are connected in parallel. Their total resistance is given by


Here R2= 3 ohm and R3=6 ohm


So


R =2 ohm


The resistance R1 is in series with the equivalent resistance which are parallel.


Total resistance of the circuit = 2+4ohms = 6ohms


(ii) Total current flowing through the circuit=Potential difference/total resistance


Here p.d =12V, and total resistance = 6 ohms


I = 12/6 = 2amps


(iii) The potential difference across R1.


V = IR1=2×4 =8V


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