Answer :

When switch is open, the upper two resistances are connected in parallel in the circuit.

Effective resistance is 1/Req=1/R+1/R=2/R


Req = R/2


So the current=I=V/(R/2)=0.6A (given)


V/R = 0.3 A


When the switch closes, the third resistance also comes in the circuit.


The effective resistance of the circuit becomes R/3


Hence, Current I = V/(R/3) = 3 (V/R) = 3 x 0.3 = 0.9 A


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