Answer :

(a) Lamp has the greatest electrical resistance as resistance oppose the flow of current, and the lamp has least amount of current.

(b) According to the given data large amount of current is needed by kettle, so it must be connected to the earthing.


(c) As we know that


P = VI


V = 240V, I = 8.5A


P = 240X8.5 = 2040 W = 2.04 kW


(d) When kettle is connected to 240 V supply, then the P = 2040 W


R = V2/P =


R = 28.23 ohm


Now, when V = 120V, R = 28.23 ohm


I = V/R = 120/28.23 = 4.25A


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Show how would yoScience - Board Papers