Answer :

(i) According to the figure.


R1 and R2 are connected in parallel.


Let I be the current following in the circuit, which is equal to 1A. After passing through the resistance R3


Current I is divided into two part say I1 and I2



(ii) Potential difference across AB = IR3 = 1 x 5 = 5V


As R1 and R2 are connected in parallel


So the equivalent resistance 1/Requivalent = 1/R1 +1/R2


1/Requivalent= 1/10 + 1/15


Requivalent= 6 ohm


Total resistance in the circuit


Rtotal= = 5+6 = 11 ohm


Potential difference across AC = IR = 1x11 = 11V


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