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Lakhmir Singh & Manjit Kaur - Physics

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Q. 164.9( 8 Votes )

In the circuit gi

Class 10th Lakhmir Singh & Manjit Kaur - Physics 1. Electricity

Answer :

A

The resistors of 6 ohm and 3 ohm are connected in parallel. Therefore, their combined resistance can be calculated as

R= 2 ohms

(b) The p.d. across the combined resistance, V= IR

Here I = 6A and combined resistance = 2 ohms.

So, V= 6 x 2 = 12 V

(c) In parallel connection potential difference remains constant, so Potential difference across 3ohm resistor =12 V

(d) The current in the 3Ω resistor

I= V/R₁

I= 12/3 =4A

(e) Current flowing through the 6 ohm resistor = V/R₂ = 12/6 = 2 A

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