Answer :

Let the individual resistance of the two resistors be R1 and R2 and their combined resistance be R. Let the total current flowing in the circuit be I and strength of the battery be V volts. Then, from Ohm's law, we have: V= IR... (1)

We know that when resistors are connected in parallel, the potential drop across each resistance is the same. Therefore: =I=I1 + I2 = V/R1 + V/R2

I = V/(1 /R1 + 1/R2) ... (2)

From the equations (1) and (2) we have:

1/R = 1 /R1 + 1/R2

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