Q. 16

# The zeroes of the polynomial p (x) = x2 + x - 6 areA. 2, 3B. -2, 3C. 2, -3D. -2, -3

Answer :

We have,

p (x) = x2 + x - 6

So, zero of the given polynomial can be calculated as follows:

x2 + x – 6 = 0

x2 + 3x – 2x – 6 = 0

x (x + 3) – 2 (x + 3) = 0

(x + 3) (x – 2) = 0

Now, x + 3 = 0

x = - 3

And, x – 2 = 0

x = 2

Hence, the zeros of the given polynomial are -3 and 2

Option C is correct

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