Answer :
We have,
p (x) = x2 + x - 6
So, zero of the given polynomial can be calculated as follows:
x2 + x – 6 = 0
x2 + 3x – 2x – 6 = 0
x (x + 3) – 2 (x + 3) = 0
(x + 3) (x – 2) = 0
Now, x + 3 = 0
x = - 3
And, x – 2 = 0
x = 2
Hence, the zeros of the given polynomial are -3 and 2
∴ Option C is correct
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