From the factor theorem, we have(x – 2) is the factor of f(x) if f(2) = 0Here, we havef(2) = (2)3 – 8= 8 – 8= 0Therefore,(x – 2) is a factor of (x3 – 8)

Q. 13.6( 16 Votes )

(x-2) is a factor of

Class 9th RS Aggarwal & V Aggarwal - Mathematics 2. Polynomials

Answer :

From the factor theorem, we have

(x – 2) is the factor of f(x) if f(2) = 0

Here, we have

f(2) = (2)³ – 8

= 8 – 8

= 0

Therefore,

(x – 2) is a factor of (x³ – 8)

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PREVIOUSThe Polynomial f(x) = x4 -2x3 +3x2 -ax + b when divided by (x-1) and (x+1) leaves the remainders 5 and 19 respectively. Find the values of a and b. Hence, find the remainder when f(x) is divided by (x-2).NEXT(x-3) is a factor of

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