Answer :

We know that,


a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 – ab – bc – ca)]


Using this formula, we get


= (a)3 + (2b)3 + (4c)3 – 3 (a) (2b) (4c)


= (a + 2b + 4c) (a2 + 4b2 + 16c2 – 2ab – 8bc – 4ac)


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