Q. 5

# If p(x) = x3

Answer :

Given, p(x) = x3 + x2 + ax + 115

(x3 + x2 + ax + 115) is exactly divisible by (x + 5)

Hence, substituting x = -5 will give us the value of a

(-5)3 + (-5)2 + a (-5) + 115 = 0

-125 + 25 5a + 115 = 0

5a = 15

a = 3

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